(2x^2+y^2)dx-(xy)dy=0

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Solution for (2x^2+y^2)dx-(xy)dy=0 equation:


Simplifying
(2x2 + y2) * dx + -1(xy) * dy = 0

Reorder the terms for easier multiplication:
dx(2x2 + y2) + -1(xy) * dy = 0
(2x2 * dx + y2 * dx) + -1(xy) * dy = 0

Reorder the terms:
(dxy2 + 2dx3) + -1(xy) * dy = 0
(dxy2 + 2dx3) + -1(xy) * dy = 0

Multiply xy * dy
dxy2 + 2dx3 + -1dxy2 = 0

Reorder the terms:
dxy2 + -1dxy2 + 2dx3 = 0

Combine like terms: dxy2 + -1dxy2 = 0
0 + 2dx3 = 0
2dx3 = 0

Solving
2dx3 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '2'.
dx3 = 0

Simplifying
dx3 = 0

The solution to this equation could not be determined.

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